On an Analogue Of the Gauss Circle Problem For the Heisenberg Groups
Об аналогe задачи о круге Гаусса для групп Гейзенберга
2019-12-12
SCID: 54.1/unjdv5nk
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Cygan–Korányi ballGauss circle problemHeisenberg groupslattice point countingsecond moment estimate
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Abstract (AI)
We consider the problem of estimating the error term $\mathcal{E}_{q}(x)=\big|\mathbb{Z}^{2q+1}\capδ_{x}\mathcal{B}\big|-\textit{vol}\big(\mathcal{B}\big)x^{2q+2}$ which occurs in the counting of lattice points in Heisenberg dilates of the Cygan-Kor{á}nyi ball. We prove three type of results regarding the order of magnitude of $\mathcal{E}_{q}(x)$, which are valid for any $q\geq3$. An upper bound estimate of the form $|\mathcal{E}_{q}(x)|\ll x^{2q-2/3}$ ; A sharp second moment estimate, which shows that $\mathcal{E}_{q}(x)$ has order of magnitude $x^{2q-1}$ in mean-square ; And an $Ω$-estimate of the form $\mathcal{E}_{q}(x)=Ω\big(x^{2q-1}\big(\log{x}\big)^{1/4}\big(\log{\log{x}}\big)^{1/8}\big)$. Consequently, we obtain the lower bound $κ_{q}=\sup\big\{α>0:\big|\mathcal{E}_{q}(x)\big|\ll x^{2q+2-α}\big\}\geq\frac{8}{3}$ for $q\geq3$, and conjecture that $κ_{q}=3$
Key Findings
1
A sharp second-moment estimate shows that E_q(x) has mean-square order of magnitude x^{2q−1}.
2
For every q≥3, the Heisenberg lattice-point error term satisfies the upper bound |E_q(x)| ≪ x^{2q−2/3}.
3
The authors conjecture that the optimal exponent is κ_q=3.
4
The error term obeys the Ω-estimate E_q(x)=Ω(x^{2q−1}(log x)^{1/4}(log log x)^{1/8}).
5
These results imply κ_q≥8/3 for q≥3, where κ_q measures the attainable power saving in the error term.
Research Object
Lattice points in Heisenberg dilates of the Cygan–Korányi ball
Research Subject
The magnitude and error-term behavior of the lattice-point counting error, including upper bounds, mean-square order, and Ω-estimates
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2019-12-12
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